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ulan@chromium.org authored
The algorithm puts elements into correct positions in multiple iterations. On the first iteration it tries to put elements at entries specified by their first hash probe. On the second iteration -- by the second hash probe, and so on. Overall it does O(k*n) memory accesses, where k is the maximum number of probes required for an element and n is the capacity of the hash table. The expectation is that k will be small. R=mstarzinger@chromium.org Review URL: https://chromiumcodereview.appspot.com/23658031 git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@16678 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
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