[debugger] simplify step over recursive function call.
The problem is this: when stepping over a recursive function call, the recursive function is flooded with one-shot break points so that we break after the call, but since the callee is the same function, the callee is also flooded, resulting a break in the callee. That however would have been a "step in" instead of "step over". The original solution was to recognize this by comparing FP. If we end up in Debug::Break, we still have to check the current FP against the remembered FP to see whether we are on the same stack height. If we are deeper, then it's not a "step over", and we do not trigger a debug break event. In that case, we queue up the step-over, and temporarily step out until we hit the desired stack height. Note that in order to step out, we flood the caller, which in our example is the same function as the callee. So we break at every flooded break location, and comparing with FP to make sure we stepped out prevents us from triggering debug break events. The new solution simply ignores breaks when the FP compare fails. We simply carry on until we hit a break where the FP compare succeeds. There is no need to do a step out. The number of calls to Debug::Break that do not trigger a debug break event due to failing FP compare is the same. But the code is a lot easier to read. R=jkummerow@chromium.org Review URL: https://codereview.chromium.org/1527253002 Cr-Commit-Position: refs/heads/master@{#32897}
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